Accleration problem - car strikes a tree

AI Thread Summary
A car traveling at 25 m/s strikes a tree, causing the driver to come to rest after traveling 0.72 m. The average acceleration of the driver during the collision is calculated using the equation for final velocity. An initial attempt yielded an incorrect acceleration of -15 m/s². The correct calculation shows that the average acceleration is approximately -434 m/s², which converts to about -44.3 g's. The discussion highlights the importance of careful calculations in physics problems.
Frosty8
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Homework Statement



A car traveling at 25m/s strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.72 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00g = 9.80 m/s2



Homework Equations



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)




The Attempt at a Solution



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)
o^2=25^2+2a(.72)
so for the acceleration i got -15ms^2/9.8ms^2= -1.53ms^2 and this was wrong. what did i do wrong?
 
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Welcome, Frosty8, to the Physics Forums!
Frosty8 said:

Homework Statement



A car traveling at 25m/s strikes a tree. The front end of the car compresses and the driver comes to rest after traveling 0.72 m. What was the average acceleration of the driver during the collision? Express the answer in terms of "g's," where 1.00g = 9.80 m/s2



Homework Equations



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)




The Attempt at a Solution



velocity final^2 = velocity initial^2 + 2acceleration(change in distance)
o^2=25^2+2a(.72)
yes, correct
so for the acceleration i got -15ms^2/9.8ms^2= -1.53ms^2 and this was wrong. what did i do wrong?
math error: 625 = -1.44a, theerfore, a = -434 m/s^2 , which is how many 'g's'?
 


Thank you
 
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