Adding a mass on an oscillation causing a change in frequency

AI Thread Summary
Attaching a mass to the end of a suspended rod decreases its oscillation frequency. The discussion centers around the relationship between mass and frequency in oscillatory systems, specifically pendulums. It is clarified that the frequency equation for a pendulum does not include mass as a variable, indicating that the frequency is independent of mass. The confusion arises from the impact of added mass on the system's moment of inertia and the resulting changes in the period of oscillation. Ultimately, the increase in mass leads to a longer period, thus decreasing the frequency of oscillation.
kavipach
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Homework Statement


A thin uniform rod of mass m is suspended from one end and oscillates with a frequency f.
If a small sphere of mass 2m is attached to the other end, does the frequency increase or decrease?

Homework Equations





The Attempt at a Solution


I have reached a conclusion that the frequency would decrease but I am not sure exactly why. Is it because the amplitude would become bigger?
 
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No, it's not because of the amplitude.

Is this talking about a pendulum? What do you know about pendulums? Any formulas?
 
i know that pendulums work due to the concervation of energy but i don't understand how this could be about a pendulum.
 
Unless the P.E becomes greater when mass and since P.E=K.E, K.E becomes greater. But i don't understand how this would change the frequency.
 
kavipach said:
Unless the P.E becomes greater when mass and since P.E=K.E, K.E becomes greater. But i don't understand how this would change the frequency.

What can you say about the period of a pendulum?
 
kavipach: What is the equation for frequency of a pendulum?

If you look closely, there are only two variables in that equation. Is mass one of them?
 
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