Insights Adding Relativity to Gravity Animation | edguy99

edguy99
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edguy99 submitted a new PF Insights post

https://www.physicsforums.com/insights/adding-relativity-to-a-gravity-animation/

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https://www.physicsforums.com/insights/adding-relativity-to-a-gravity-animation/
 
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edguy99 said:
edguy99 submitted a new PF Insights post

https://www.physicsforums.com/insights/adding-relativity-to-a-gravity-animation/

https://www.physicsforums.com/insights/wp-content/uploads/2015/05/relativityanimation-80x80.png https://www.physicsforums.com/insights/adding-relativity-to-a-gravity-animation/

I'm looking forward to the Einstein and quantum gravity comparative. I've just recently taken the perspective of gravity not being a geometric effect on spacetime specifically, but instead a field that affects the kinematics via...not spacetime.
 
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Looking forward to the Einstein’s gravity and quantum mechanic comparative!
 
OK, so this has bugged me for a while about the equivalence principle and the black hole information paradox. If black holes "evaporate" via Hawking radiation, then they cannot exist forever. So, from my external perspective, watching the person fall in, they slow down, freeze, and redshift to "nothing," but never cross the event horizon. Does the equivalence principle say my perspective is valid? If it does, is it possible that that person really never crossed the event horizon? The...
ASSUMPTIONS 1. Two identical clocks A and B in the same inertial frame are stationary relative to each other a fixed distance L apart. Time passes at the same rate for both. 2. Both clocks are able to send/receive light signals and to write/read the send/receive times into signals. 3. The speed of light is anisotropic. METHOD 1. At time t[A1] and time t[B1], clock A sends a light signal to clock B. The clock B time is unknown to A. 2. Clock B receives the signal from A at time t[B2] and...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...

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