Adding two lines, what is the equation of the new line?

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The discussion revolves around finding an equation that relates the speed of a vehicle to its overall distance, which is the sum of thinking distance and braking distance. The user has derived two separate equations: one for speed versus thinking distance and another for speed versus braking distance. There is a suggestion to clarify the variables used to avoid confusion. Ultimately, the user resolves the issue and thanks the participants for their input. The conversation highlights the importance of clear variable distinction in mathematical equations.
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Homework Statement



Basically I was given a table displaying speed of a vehicle, thinking distance (distance it takes for driver to react) and braking distance. I am told to find an equation relating speed of vehicle and overall distance (overall distance = thinking distance + braking distance).



The Attempt at a Solution



Using graphing software, I've managed to find an approximate equation relating speed and thinking distance, as well as an equation relating speed and braking distance.

The equations are :

For speed vs thinking dist., y = (16/3)x, where y is speed of vehicle and x is thinking distance
and
For speed vs braking dist., y = 13(x^0.5), where y is the speed of vehicle and x is braking distance



Is there any way I can find an equation for speed versus overall distance using these 2 equations that I've obtained?
 
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saplingg said:
Is there any way I can find an equation for speed versus overall distance using these 2 equations that I've obtained?
Sure. It might be more obvious if you didn't use the same letter to denote thinking distance and braking distance.

(And shouldn't those constants have some units on them?)
 
Could anyone show me how?

@Hurkyl: I used subscripts to distinguish the distances
 
You are talking about the TOTAL distance aren't you?

(And you titled this "ADDING two lines"!)
 
yeah what is wrong with that?
 
Err It's ok, I've solved it. Thanks to all who read
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks
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