I Adiabatic cooling in this process involving liquid ammonia

AI Thread Summary
The discussion centers on the adiabatic cooling process of liquid ammonia, starting from specific entry conditions of 1 bar and -34 degrees Celsius. The process involves heating the ammonia to 4.5 degrees Celsius at 10 bar, followed by expansion into an empty vessel until the pressure equalizes at 1 bar. Participants question whether the exit temperature will always be higher than the entry temperature due to inefficiencies and if a load on the expander could allow for a lower exit temperature. Clarifications about the p-H diagram indicate that point B should represent saturated liquid ammonia, not gas, and the final average temperature after the process is still under consideration. The conversation emphasizes the need for precise thermodynamic analysis to understand the behavior of ammonia throughout the process.
aladinlamp
Messages
44
Reaction score
1
TL;DR Summary
Adiabatic cooling
Entry conditions: liquid ammonia , 1 bar , temp -34 celsius,
i supply heat Q to heat it to 4.5 celsius, 10 bar,
than i release it into empty vessel until inside reaches also 1 bar,
expansion,adiabatic cooling, uses internal energy of ammonia to expand and cool itself

1. can we assume, after this cycle finishes, exit temperature of ammonia will be always higher than entry temperature, since this process is not fully reversible, not 100% efficient ?
2. can we achieve exit temperature lower than entry temp, if we use expander with load, to extract even more internal energy from gas?
 
Science news on Phys.org
Please provide more details of the process. For example, show end points of each step in p-H diagram, and describe better what is the process for each step.
 
Chestermiller said:
Please provide more details of the process. For example, show end points of each step in p-H diagram, and describe better what is the process for each step.
Hi, I made some errors in setting up my initial conditions, so let's reevaluate them step by step. In the diagram, there are two points, A and B:

  • Point A represents a 1-liter container filled with liquid ammonia at a pressure of 1 Bar and a temperature of 240 Kelvin. Heat, denoted as Q1, is added to the ammonia to increase its temperature.
  • Point B represents a 1-liter container filled only with gaseous ammonia at a pressure of 20 Bar and a temperature of 323 Kelvin.
I'm trying to determine a new point C on the chart under these assumptions:

  • The heat exchange occurs only within the ammonia itself.
  • The ammonia from the 1-liter container is released through a valve into another container until the pressure in both containers equalizes at 1 Bar. Eventually, there will be ammonia at 1 Bar pressure in a both volumes.
My question is: What will be the average temperature of ammonia in both containers at the end of this process, where is next point C ?
ab.png
 
Last edited:
aladinlamp said:
Hi, I made some errors in setting up my initial conditions, so let's reevaluate them step by step. In the diagram, there are two points, A and B:

  • Point A represents a 1-liter container filled with liquid ammonia at a pressure of 1 Bar and a temperature of 240 Kelvin. Heat, denoted as Q1, is added to the ammonia to increase its temperature.
aladinlamp said:
  • Point B represents a 1-liter container filled only with gaseous ammonia at a pressure of 20 Bar and a temperature of 323 Kelvin.
Point B on the p-H diagram represents saturated liquid, not gas.
 
ok, where is correct location of point B ?
 
aladinlamp said:
ok, where is correct location of point B ?
On the right hand side of the saturation envelope, not the left hand side. But, of course, for the same mass of ammonia at points A and B, the volume at B will be much larger than 1 liter.
 
I need to calculate the amount of water condensed from a DX cooling coil per hour given the size of the expansion coil (the total condensing surface area), the incoming air temperature, the amount of air flow from the fan, the BTU capacity of the compressor and the incoming air humidity. There are lots of condenser calculators around but they all need the air flow and incoming and outgoing humidity and then give a total volume of condensed water but I need more than that. The size of the...
Thread 'Why work is PdV and not (P+dP)dV in an isothermal process?'
Let's say we have a cylinder of volume V1 with a frictionless movable piston and some gas trapped inside with pressure P1 and temperature T1. On top of the piston lay some small pebbles that add weight and essentially create the pressure P1. Also the system is inside a reservoir of water that keeps its temperature constant at T1. The system is in equilibrium at V1, P1, T1. Now let's say i put another very small pebble on top of the piston (0,00001kg) and after some seconds the system...
Back
Top