Adjusting Telescoping Antenna Length

AI Thread Summary
To maximize FM radio reception at 100 MHz, the telescoping antenna should be adjusted to approximately 1.43 meters in length, calculated using the formula 143/frequency. However, it's important to understand the concept of wavelength and that the ideal antenna length is typically 1/4 of the wavelength. The electrical length of the antenna is about 95% of its physical length, which may affect the final adjustment. Users are advised to review their textbooks for a better understanding of antenna theory before attempting such calculations. Proper knowledge of the formulas and their applications is crucial for effective antenna length adjustments.
Sevendust
Messages
3
Reaction score
0

Homework Statement



"Your vacation cabin in the woods is at the very fringe of the reception area for the FM radio station in the previous question (that broadcasts at 100 mHz). In order to maximize your chances of receiving your favorite tunes clearly from this station, you should adjust the telescoping antenna of your portable radio to ____ meters in length."

Homework Equations



I missed class, so after some googling I found an equation online that stated that 143/frequency gives me the length in meters.

The Attempt at a Solution



143/100mhz = 1.43
I entered this and it was incorrect. Any help/equations I can use?
 
Last edited:
Physics news on Phys.org
Sevendust said:
googling I found an equation online that stated 468/frequency gives me the length in feet, and 143/frequency gives me the length in meters.

Hi Sevendust! http://img96.imageshack.us/img96/5725/red5e5etimes5e5e45e5e25.gif

Did you find what fraction λ is best for the whip antenna? Won't you need to know whether the answer should be in feet or metres, before entering it in an online quiz?

http://en.wikipedia.org/wiki/Whip_antenna
 
Last edited by a moderator:
Hey :), the answers going to be in metres, sorry if I made that vague in my first post. I'm not exactly sure what you mean by finding the fraction λ: can you explain?
 
fraction of λ = fraction of wavelength
 
You shouldn't use random formulas without understanding them. You should review your textbook before trying the problem.

The kind of antenna in question is usually 1/4 of the wavelength of the expected signal. You know the frequency, so you can calculate the wavelength. You may also need the rule of thumb that the electrical length of an antenna is about 95% of the physical length.
 
Got it: thanks for your help guys. I need to find a classmate with the notes so I can review for the test. Cheers.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Struggling to make relation between elastic force and height'
Hello guys this is what I tried so far. I used the UTS to calculate the force it needs when the rope tears. My idea was to make a relationship/ function that would give me the force depending on height. Yeah i couldnt find a way to solve it. I also thought about how I could use hooks law (how it was given to me in my script) with the thought of instead of having two part of a rope id have one singular rope from the middle to the top where I could find the difference in height. But the...

Similar threads

Back
Top