Advanced Heat Transfer - Conduction Cooling in Turbine Blade

AI Thread Summary
The discussion centers on solving a second-order ordinary differential equation (ODE) related to heat transfer in a turbine blade modeled as a one-dimensional fin. The user successfully derived the homogeneous solution but struggled with the non-homogeneous part, seeking advice on methods to find the particular solution. Key equations were discussed, including energy balances and boundary conditions necessary for solving the ODE. The conversation highlighted the importance of correctly applying boundary conditions and addressing potential complications in the heat transfer equations. Ultimately, the user reported successfully solving the problem using hyperbolic functions after clarifying their approach with forum members.
MechanicalMan
Messages
25
Reaction score
0
I am trying to solve an advanced heat transfer problem and I have a 2nd order ODE. I can solve the homogeneous solution easily, but I am having trouble with the non-homogeneous solution.

Homework Statement


Given a turbine blade and asked to model as a one-dimensional fin, subject to the following constraints:

Troot = 900 deg F
Lfin = 3.6 in
A = 0.506 in^2
Tg (external gas flowing over the fin/blade) = 1500 deg F
Pfin = 2.1 in
k = 8.1 BTU/hr ft deg F
h = 36.6 BTU/hr ft^2 deg F

There is a small element dx with the following thermal energy in/out of it: qx coming out in the negative x-direction, qg into it from the ambient and q(x+dx) coming into the element. At the root, there is a value q0 transferring into the disk through conduction. The temperature along the length of the blade is a function of x.

Homework Equations



Energy balance on small element dx

The Attempt at a Solution



This is what I have so far:
qin = qout
h[T(x) - Tg]Pdx + [(qx - ∂qx/∂x)A] = - qxA
h[T(x) - Tg]P + ∂qx/∂x*A = 0
h[T(x) - Tg]P + ∂/∂x{-k∂T(x)/∂x}A = 0
h[T(x) - Tg]P - k (∂2T/∂x2)A = 0
d2T/dx2 - (hP/Ak)*T(x) = -(hP/Ak)*Tg

I know that the solution to this non-homogeneous ODE is a combination of the complimentary solution and the particular solution. The roots of the homogeneous ODE yield:

r = +/- (hP/Ak)^1/2

Therefore the complementary portion of the solution is

T(x) = C1e^(hP/Ak)^0.5 + C2e^(hP/Ak)^0.5

I'm stuck now trying to find the particular solution. I am not sure which method to use. I tried variation of parameters but I can't seem to get something that makes sense. I know I should end up with a hyperbolic function, but I'm stuck. Any ideas?
 
Physics news on Phys.org
MechanicalMan said:
I am trying to solve an advanced heat transfer problem and I have a 2nd order ODE. I can solve the homogeneous solution easily, but I am having trouble with the non-homogeneous solution.


Homework Statement


Given a turbine blade and asked to model as a one-dimensional fin, subject to the following constraints:

Troot = 900 deg F
Lfin = 3.6 in
A = 0.506 in^2
Tg (external gas flowing over the fin/blade) = 1500 deg F
Pfin = 2.1 in
k = 8.1 BTU/hr ft deg F
h = 36.6 BTU/hr ft^2 deg F

There is a small element dx with the following thermal energy in/out of it: qx coming out in the negative x-direction, qg into it from the ambient and q(x+dx) coming into the element. At the root, there is a value q0 transferring into the disk through conduction. The temperature along the length of the blade is a function of x.


Homework Equations



Energy balance on small element dx


The Attempt at a Solution



This is what I have so far:
qin = qout
h[T(x) - Tg]Pdx + [(qx - ∂qx/∂x)A] = - qxA
Shouldn't this be
h[Tg - T(x)] P dx + qx A = [ qx - (dqx/dx) dx ]A
I.e.,
Heat in from ambient
+ Heat in from the +x side
= Heat out the -x side​

You seem to have some of your +/- signs off, plus there was a dx term missing in the "Heat out" expression. Also, partial derivatives don't apply since x is the only dependent variable.

h[T(x) - Tg]P + ∂qx/∂x*A = 0
h[T(x) - Tg]P + ∂/∂x{-k∂T(x)/∂x}A = 0
h[T(x) - Tg]P - k (∂2T/∂x2)A = 0
d2T/dx2 - (hP/Ak)*T(x) = -(hP/Ak)*Tg
I agree with this, so it looks like you just had some typos in posting your earlier part of the calculation.

I know that the solution to this non-homogeneous ODE is a combination of the complimentary solution and the particular solution. The roots of the homogeneous ODE yield:

r = +/- (hP/Ak)^1/2

Therefore the complementary portion of the solution is

T(x) = C1e^(hP/Ak)^0.5 + C2e^(hP/Ak)^0.5
I don't know if you really meant to write it this way. Where is the negative-root solution? Where is the x in the exponent terms?

I'm stuck now trying to find the particular solution. I am not sure which method to use. I tried variation of parameters but I can't seem to get something that makes sense. I know I should end up with a hyperbolic function, but I'm stuck. Any ideas?

Since there are two constants to find (C1 and C2), we need two boundary conditions. An obvious one is the temperature at the base of the fin. Another one would relate to the heat transfer at the fin tip. Find equations to express those conditions, and you should be able to get C1 and C2.
 
Redbelly98 said:
Shouldn't this be
h[Tg - T(x)] P dx + qx A = [ qx - (dqx/dx) dx ]A
I.e.,
Heat in from ambient
+ Heat in from the +x side
= Heat out the -x side​

You seem to have some of your +/- signs off, plus there was a dx term missing in the "Heat out" expression. Also, partial derivatives don't apply since x is the only dependent variable.


I agree with this, so it looks like you just had some typos in posting your earlier part of the calculation.


I don't know if you really meant to write it this way. Where is the negative-root solution? Where is the x in the exponent terms?



Since there are two constants to find (C1 and C2), we need two boundary conditions. An obvious one is the temperature at the base of the fin. Another one would relate to the heat transfer at the fin tip. Find equations to express those conditions, and you should be able to get C1 and C2.

Thanks, I did make some typos in the original statement, which is why it may seem off at some points. I did miss the negative root and I did miss the x in the exponent of my original post. I have the boundary conditions, but my only concern is that if I relate the heat transfer by convection at the tip to the conduction through the fin, I'll have an expression that is dependent on x. I do not know what T(L) is, so if I make that substitution, do I not just complicate the problem even more?
 
MechanicalMan said:
I do not know what T(L) is, so if I make that substitution, do I not just complicate the problem even more?
That's right, T(L) is not one of the boundary conditions.

Consider the dx element at the very tip of the fin. What is qx entering into that element (from the x+ direction)?
 
Redbelly98 said:
That's right, T(L) is not one of the boundary conditions.

Consider the dx element at the very tip of the fin. What is qx entering into that element (from the x+ direction)?

I managed to solve the problem, and after pages and pages of algebra, I have the solution in terms of hyperbolic functions. Thanks for the tips.
 

Similar threads

Replies
13
Views
2K
Replies
2
Views
2K
Replies
1
Views
4K
Replies
21
Views
5K
Replies
1
Views
2K
Replies
2
Views
5K
Replies
16
Views
3K
Back
Top