Air flow pipe size reduction|Incompressible&Lossless COMPLETED ANSWER

AI Thread Summary
The discussion focuses on a homework problem involving airflow through a duct that reduces in size from 0.75 m² to 0.20 m². The calculated pressure change, assuming incompressible flow, is 130.625 Pascals, though this value seems low given the context. The incompressibility assumption is questioned, as the density of air suggests it may compress under flow conditions. For the force transmitted when the jet strikes a wall, a dynamic pressure of 140.625 Pa is calculated, leading to a force of 28.125 N, although concerns about ignoring static pressure are raised. Overall, the calculations demonstrate the complexities of fluid dynamics in duct systems.
DylanW
Messages
22
Reaction score
0

Homework Statement



Q4. A horizontal air duct reduces from 0.75 m2
to 0.20 m2
.
a) Assuming no losses and an incompressible fluid, what pressure change will occur when 6 kg/s
of air flows through the duct? Use a density of 3.2 kg/m3
for these conditions.
b) Is the incompressible assumption justified?
c) If the jet exits the smaller pipe and strikes a vertical wall, what force will it transmit?


Homework Equations



MassFlowRate = rho.V.A
Bernoullis



The Attempt at a Solution



rho(A).Velocity(A).Area(A)=mass flowate therefore Velocity(A) = 2.5
Mass Flow Rate is Constant
rho(A).Velocity(A).Area(A)=rho(B).Velocity(B).Area(B) therefore Velocity(B) = 9.375
Bernoullis - can't be bothered typing original equation will just type final rearrangement
Pressure(A) - Pressure(B) = [(Velocity(B)^2 - Velocity(A)^2)Rho]/2 which equals 130.625 Pascals pressure difference. Seems a bit low?

For part b, is the incompressible assumption justified? I don't think that it is, because it's density it is a gas and would definitely compress which may explain the results from part A?

For Part C) I'm not so sure of this, I think it would be the Absolute pressure over the area of the Jet so (x Pascals / 0.2 m^2) but I am not sure how to find the absolute pressure, only the difference. Thanks :D
 
Physics news on Phys.org
For Part C, I've used the equation P(Dynamic) = [rho.V^2]/2 giving a dynamic pressure of 140.625 Pa and verifying my answer from part 1. Then Using P=F/A -> F = PA I've calculated a force of 28.125N. I am worried that I am ignoring static pressure but I can't see any other way with the information provided.
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...
Back
Top