(adsbygoogle = window.adsbygoogle || []).push({}); Airplane Free-body diagram!!

1. The problem statement, all variables and given/known data

A plane with mass of1090 kgis flying straight and level at an altitude of 1100 meters & a constant velocity of200 kg/hr(55.55m/sec).Assuming that the acceleration due to gravity is10 m/sec^2, the force on the plane due to gravity is10900 Newtons. Since the plane is in level flight, the net force in the y direction is 0 & the lifting force provided by the wings equals the weight of the plane. The piolot now banks the wings at a7.5 degreeangle w/ respect to the vertical in order to make a turn. Part of the lifting force of the wings is now used to make the plane turn in a circle & theres less lift to counteract the force of gravity.

How long will it take the plane to make one turn of360 degreesat a velocity of 200 km/hr (55.55 m/sec)??

2. Relevant equations

Vf=Vo+aT

S=Vo(T)+1/2(a)(T)^2

s=theta(r)

Time=Distance/radius

A free-body diagram of the situation:

3. The attempt at a solution

NO CLUE!!!!!!!!!!!!HELP!!!

All I know is that the value that the lift should be increased so that the plane doesn't decend is10994 Newtonsand that theradiusof the circle that the plane will fly w/o loosing altitude w/ constant velocity of 200km/hr is2343 m.

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# Airplane Free-body diagram

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