To find x + y when xy = 1,000 and neither x nor y can have 10 as a factor, the prime factorization of 1,000 is 2^3 * 5^3. The factors must be divided into two sub-lists, ensuring that one sub-list contains only 2s and the other only 5s to avoid multiples of 10. This results in x = 8 (from 2*2*2) and y = 125 (from 5*5*5). Therefore, x + y equals 133. The solution adheres to the given constraints and correctly identifies the values of x and y.