How to Find x + y When xy = 1,000 Without Using 10 as a Factor?

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To find x + y when xy = 1,000 and neither x nor y can have 10 as a factor, the prime factorization of 1,000 is 2^3 * 5^3. The factors must be divided into two sub-lists, ensuring that one sub-list contains only 2s and the other only 5s to avoid multiples of 10. This results in x = 8 (from 2*2*2) and y = 125 (from 5*5*5). Therefore, x + y equals 133. The solution adheres to the given constraints and correctly identifies the values of x and y.
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If x and y are whole numbers that don't have10 as a factor, and if xy = 1,000, find x + y.
 
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Make a list of prime factors of 1000. Distribute this into two sub-lists. Make sure that neither sub-list contains a 2 and 5 in the same sub-list. Hint, there are 6 prime factors, only two distinct, and only one way to divy them up according to these rules.
 
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I need more help.!
 
This is what turin means

1000 = 5*5*5*2*2*2

To distribute this into sublists looks like this:

Code:
2         2*2*5*5*5
2*2      2*5*5*5

But we can't have both 2 and 5 in either sublists (that would give us a multiple of 10).

So the only way to resolve this is to have all the two's in one sublist and the three 5's in the other sublists, so we have: 2*2*2= 8 and 5*5*5 = 125.

x = 8, y=125
 
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