Algebra and Permutations: Determining the Parity of an Element in S_n

decerto
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Homework Statement



Suppose σ is an element of S_n, if σ^5=1, is σ necessarily odd or even

Homework Equations



Parity(\sigma)= (\sum_{i=1}^k(|c_i|-1)) mod 2

The Attempt at a Solution



Really unsure how to even start this, I think I have to use the fact you can decompose every permutation into a product of disjoint or 2 cycles and use their properties to show in what cases it's even or odd but I'm not really sure.
 
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decerto said:

Homework Statement



Suppose σ is an element of S_n, if σ^5=1, is σ necessarily odd or even

Homework Equations



Parity(\sigma)= (\sum_{i=1}^k(|c_i|-1)) mod 2

The Attempt at a Solution



Really unsure how to even start this, I think I have to use the fact you can decompose every permutation into a product of disjoint or 2 cycles and use their properties to show in what cases it's even or odd but I'm not really sure.

##\sigma^5=\sigma \sigma \sigma \sigma \sigma=1##. ##1## is an even permutation. Suppose ##\sigma## were odd. Then what would be the parity of ##\sigma^5##?
 
What does σ5 being even tell you?
 
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There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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