Algebraic Expression: Pattern for Term t

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The discussion focuses on finding the algebraic expression for the term t in the sequence -15, 30, 90, -360. The pattern involves each term being derived by multiplying the previous term by the current term number, with alternating signs based on whether the term number is even or odd. Specifically, the sequence can be represented as a_n = n * a_{n-1}, with the first term a_1 = -15. The signs follow a pattern that can be expressed using a power of -1 related to n. The goal is to formulate a complete expression for the nth term based on these observations.
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Homework Statement



In this pattern, what is the algebraic expression for the term t?
-15, 30, 90, -360

Homework Equations



t= term number

The Attempt at a Solution



no idea
 
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What do you multiply each term by to get the next?
 
DivisionByZro said:
What do you multiply each term by to get the next?
That's what I want to find out. It does not necessarily have to be multiplication only.

In words it would be:
current term value = the previous term's value multiplied by the current term number, and change poles if the current term number is even; the first term value is -15.
 
Are you saying that you have a sequence, a_1= -15, a_2= 30, a_3= 90, and a_4= -360?

Well, I notice that 30= 2*15, 90= 3*30, and 360= 4*90. That is, a_n= n*a_{n-1}. Also, the signs are -, +, +, -. You should be able to find a power of -1, in terms of n, that will give that.
 
HallsofIvy said:
Are you saying that you have a sequence, a_1= -15, a_2= 30, a_3= 90, and a_4= -360?

Well, I notice that 30= 2*15, 90= 3*30, and 360= 4*90. That is, a_n= n*a_{n-1}. Also, the signs are -, +, +, -. You should be able to find a power of -1, in terms of n, that will give that.

So what would the algebraic expression to find the nth term be?
 
I tried to combine those 2 formulas but it didn't work. I tried using another case where there are 2 red balls and 2 blue balls only so when combining the formula I got ##\frac{(4-1)!}{2!2!}=\frac{3}{2}## which does not make sense. Is there any formula to calculate cyclic permutation of identical objects or I have to do it by listing all the possibilities? Thanks
Since ##px^9+q## is the factor, then ##x^9=\frac{-q}{p}## will be one of the roots. Let ##f(x)=27x^{18}+bx^9+70##, then: $$27\left(\frac{-q}{p}\right)^2+b\left(\frac{-q}{p}\right)+70=0$$ $$b=27 \frac{q}{p}+70 \frac{p}{q}$$ $$b=\frac{27q^2+70p^2}{pq}$$ From this expression, it looks like there is no greatest value of ##b## because increasing the value of ##p## and ##q## will also increase the value of ##b##. How to find the greatest value of ##b##? Thanks

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