Algebraic method to balance redox equations

  • Thread starter diffrac
  • Start date
  • #1
9
0

Main Question or Discussion Point

Hi all,

I'm learning how to solve redox equations. I found the algebraic method to solve equations such as this one:
Fe[itex]^{2+}[/itex] + Cr[itex]_{2}[/itex]O[itex]_{7}[/itex][itex]^{2-}[/itex] +H[itex]^{+}[/itex][itex]\rightarrow[/itex] Fe[itex]^{3+}[/itex] + Cr[itex]^{3+}[/itex] + H[itex]_{2}[/itex]0
and i was able to solve it.

What I don't see is how to use that algebraic method to solve an equation without superscripts; since it doesn't allow you to balance the charges, right?
like for example: NaOH + Cr(OH)[itex]_{3}[/itex] + NaClO[itex]\rightarrow[/itex] Na[itex]_{2}[/itex]CrO[itex]_{4}[/itex] +NaCl + H[itex]_{2}[/itex]O

Thanks for your help.
 

Answers and Replies

  • #2
Borek
Mentor
28,398
2,800
If everything is neutral (on both sides of the reaction) there is no need to separately balance the charge. But you can always write an additional identity

[tex]0\times a_1 + 0\times a_2 + ... = 0\times b_1 + 0\times b_2 + ...[/tex]

(assuming ai are stoichiometric coefficients on the LHS of the equation, and bi are coefficients on the RHS).

Compare ChemBuddy lecture on the algebraic method of reaction equation balancing - it shows how to balance both equations with charged and uncharged species.

Use [noparse] and [/noparse] tags to format the formulas, don't mix normal text with LaTeX, it is not guaranteed to work OK.
 

Related Threads on Algebraic method to balance redox equations

  • Last Post
Replies
1
Views
1K
  • Last Post
Replies
1
Views
2K
Replies
3
Views
7K
Replies
1
Views
2K
  • Last Post
Replies
2
Views
2K
  • Last Post
Replies
0
Views
2K
  • Last Post
Replies
4
Views
21K
  • Last Post
Replies
9
Views
2K
  • Last Post
Replies
1
Views
4K
  • Last Post
Replies
5
Views
16K
Top