- #1
diffrac
- 9
- 0
Hi all,
I'm learning how to solve redox equations. I found the algebraic method to solve equations such as this one:
Fe[itex]^{2+}[/itex] + Cr[itex]_{2}[/itex]O[itex]_{7}[/itex][itex]^{2-}[/itex] +H[itex]^{+}[/itex][itex]\rightarrow[/itex] Fe[itex]^{3+}[/itex] + Cr[itex]^{3+}[/itex] + H[itex]_{2}[/itex]0
and i was able to solve it.
What I don't see is how to use that algebraic method to solve an equation without superscripts; since it doesn't allow you to balance the charges, right?
like for example: NaOH + Cr(OH)[itex]_{3}[/itex] + NaClO[itex]\rightarrow[/itex] Na[itex]_{2}[/itex]CrO[itex]_{4}[/itex] +NaCl + H[itex]_{2}[/itex]O
Thanks for your help.
I'm learning how to solve redox equations. I found the algebraic method to solve equations such as this one:
Fe[itex]^{2+}[/itex] + Cr[itex]_{2}[/itex]O[itex]_{7}[/itex][itex]^{2-}[/itex] +H[itex]^{+}[/itex][itex]\rightarrow[/itex] Fe[itex]^{3+}[/itex] + Cr[itex]^{3+}[/itex] + H[itex]_{2}[/itex]0
and i was able to solve it.
What I don't see is how to use that algebraic method to solve an equation without superscripts; since it doesn't allow you to balance the charges, right?
like for example: NaOH + Cr(OH)[itex]_{3}[/itex] + NaClO[itex]\rightarrow[/itex] Na[itex]_{2}[/itex]CrO[itex]_{4}[/itex] +NaCl + H[itex]_{2}[/itex]O
Thanks for your help.