All Subgroups of S3: Lagrange's Theorem Explained

  • Thread starter Thread starter e179285
  • Start date Start date
  • Tags Tags
    Subgroup
e179285
Messages
24
Reaction score
0
The question wants all subgroups of S3 . If H≤S 3 , then ; IHI=1,2,3,6 by Lagrance's Theorem.

In other words, order of H can be 1,2,3 and 6.

What ı want to ask is how to write subgroup of S3. For example,is H 1 (1) ?
 
Physics news on Phys.org
For "H_1", yes, any subgroup must contain the identity so if H contains only one member, it must be just the identity permutation, (1).

There are, in fact, 3 different subgroups of order 2: {e, (12)}, {e, (13)}, and {e, (23)}. There is the single subgroup of order 3: {e, (123), (132)}. Of course, the subgroup of order 6 is the entire group.
 
HallsofIvy said:
For "H_1", yes, any subgroup must contain the identity so if H contains only one member, it must be just the identity permutation, (1).

There are, in fact, 3 different subgroups of order 2: {e, (12)}, {e, (13)}, and {e, (23)}. There is the single subgroup of order 3: {e, (123), (132)}. Of course, the subgroup of order 6 is the entire group.

What can H5 be?
 
? You just said that every subgroup of S3 (every subgroup of any group of order 6) must have order 1, 2, 3, or 6 (a divisor of 6). What do you mean by "H5"?
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top