What Is the Maximum Speed of an Alpha Particle with 2.34 MeV Kinetic Energy?

AI Thread Summary
The discussion centers on calculating the maximum speed of an alpha particle with a kinetic energy of 2.34 MeV. The relevant equation used is kinetic energy (KE) = 1/2 mv^2, which was initially misapplied. The correct formula includes a factor of 2, leading to the confusion. The user realizes their mistake in not using the correct kinetic energy formula. Ultimately, the correct approach clarifies the calculation for determining the alpha particle's speed.
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Homework Statement



An Alpha Particle is emitted with a kinetic energy of 2.34 MeV during a radioactive decay process. The maximum speed of the alpha particle is?

Homework Equations



KE=mv2
1 ev = 1.6x10-19j

The Attempt at a Solution


\sqrt{(2.34x10^6)(1.6x10^-19)/4(1.6x10^-27)}

Unfortunately the manual uses this solution for the problem:

\sqrt{2(2.34x10^6)(1.6x10^-19)/4(1.6x10^-27)}

Could anyone explain to me where the 2 comes from?
 
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Nevermind... I see what I did wrong..

KE= 1/2 mv^2 DUHHHH
 

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