Altitude of rocket with 2E5 N thrust

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SUMMARY

The discussion focuses on calculating the altitude of a Polaris missile with a mass of 1.4 x 104 kg and a thrust of 2 x 105 N, firing vertically for 1 minute. The upward acceleration is determined using the equation a = (F - W) / m, resulting in an acceleration of 4.49 m/s2. The calculated altitude during the thrust phase is approximately 8074 m, but the correct total altitude, accounting for free fall after engine shutdown, is 11.8 km.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Knowledge of gravitational force (W=mg)
  • Familiarity with kinematic equations (y=0.5at2)
  • Basic concepts of free fall and projectile motion
NEXT STEPS
  • Study the effects of air resistance on rocket flight
  • Learn about the kinematic equations for projectile motion
  • Explore thrust-to-weight ratio calculations in rocketry
  • Investigate the principles of vertical launch dynamics
USEFUL FOR

Students in physics, aerospace engineering enthusiasts, and anyone interested in rocketry and motion dynamics will benefit from this discussion.

astenroo
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Homework Statement



A polaris missile has a mass of 1.4 x 10^4 kg and its engine has a thrust of 2 x 10^5 N. If its engines fire in the vertical direction for 1 min starting from rest, to what vertical height would it rise in the absence of air resistance?

Homework Equations



F=ma
W=mg
y=.5at^2

The Attempt at a Solution



So, I figured F-W=ma, where a is the upward acceleration, F is the thrust, W is the wight of the rocket and m is the mass of the rocket. This would produce a total upward acceleration of a= (F-W)/m=4.49 m/s^2. The distance y is then y=0.5 x 4,49 x 60^2=8074 m. The correct answer should be 11.8 km (3.7 km in free fall).

Where am I thinking wrong here?
 
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I have to find the velocity after its engine shuts down. The final velocity should be 0, so taking the following equation v^2=v0^2-2g(x-x0), where v0 is the velocity when the engines shut down, x0 is the altitude gained during thrust phase.
x=(v0^2)/2g + x0 = roughly 11.8 km.
 

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