Aluminium Oxide as a dielectric

  • Context: Undergrad 
  • Thread starter Thread starter tommyers
  • Start date Start date
  • Tags Tags
    Aluminium Dielectric
Click For Summary

Discussion Overview

The discussion revolves around the measurement of capacitance in parallel plate capacitors, specifically focusing on the potential impact of aluminium oxide as a dielectric in conjunction with air. Participants explore the discrepancies between expected and measured capacitance values and investigate the influence of parasitic capacitance in the measurement setup.

Discussion Character

  • Exploratory
  • Technical explanation
  • Debate/contested
  • Mathematical reasoning

Main Points Raised

  • Tom initially expected a capacitance of approximately 7.9pF but measured 65pF, leading him to question the role of aluminium oxide as a dielectric alongside air.
  • Michel suggests that the capacitance formula for multiple dielectric layers could apply, depending on the thickness of the layers, but notes that if air is significantly thicker, it may dominate the capacitance measurement.
  • Tom clarifies that the setup consists of two parallel aluminium plates separated by air, with a potential thin layer of aluminium oxide on the surface.
  • Another participant questions the measurement method, prompting Tom to describe his use of a capacitance meter with a zero-adjust feature.
  • Concerns are raised about parasitic capacitance from the measurement setup, including the influence of coaxial cables and connectors, which could significantly affect the readings.
  • Tom mentions using a commercially available capacitance meter and questions whether the excitation voltage from the meter affects the readings.
  • Michel emphasizes the importance of ensuring the reliability of the measurement method and suggests testing with known capacitances to validate the setup.
  • Participants discuss the challenges of canceling out parasitic capacitance, particularly when it is much larger than the capacitance being measured.
  • Tom acknowledges the zeroing mechanism of the meter is user-adjusted, which raises further questions about its effectiveness in eliminating larger parasitic capacitances.
  • Additional resources are shared to help Tom improve his experimental setup and measurement techniques.

Areas of Agreement / Disagreement

Participants express varying opinions on the impact of aluminium oxide as a dielectric and the reliability of measurement techniques. There is no consensus on the best approach to mitigate parasitic capacitance, and the discussion remains unresolved regarding the accuracy of Tom's measurements.

Contextual Notes

Participants highlight limitations related to the geometry of the capacitor setup, the thickness of dielectric layers, and the potential influence of measurement equipment on results. The discussion reflects ongoing uncertainties and assumptions about the measurement process and its implications.

tommyers
Messages
57
Reaction score
0
Hi,

I have been doing some experimentation with parallel plate capacitors, see https://www.physicsforums.com/showthread.php?t=124150"

For one arrangement of aluminium plates (air as the dielectric) I was expecting the measured capacitance to be approx. 7.9pF and what I measured was 65pF. Do you think that aluminium oxide (dielectric 9.1) was adding to the air dielectric of 1.

So instead of my calculations using 1 I should have used 9.1 which would have brought my theory nearer my practise?

Regards

Tom
 
Last edited by a moderator:
Physics news on Phys.org
Hello Tom,

Assume that there are three dielectric layers {1,2,3} in between two conducting plates of area A.
Then the capacity of this system is given by:

[tex]C = A \frac{1}{\frac{d_1}{\epsilon_1}+\frac{d_2}{\epsilon_2}+\frac{d_3}{\epsilon_3}}[/tex]

From your explanation, I don't see clearly the geometry you consider, but I guess it is a series of layers, isn't it? If this is correct, then this formula applies. It shows clearly that the capacity can indeed vary between that for air and that for Al2O3 depending simply on the thickness of the layers. I don't know the thickness of air and Al2O3 you consider, but if air is much thicker than the Al2O3 layers, the capacity would be dominated by the air.

Hope it helps,

Michel
 
Hi Michel,

The geometry is basically two parallel aluminium plates separated by air. I was then wondering if the surface of the plates had an oxide (aluminium oxide, 9.1) on them, this could be thought of as the dielectric.

Regards

Tom
 
How are you doing the measurement?
 
Hi tom,

Clearly the thin oxide layer on your plate has a negligible effect.
You should investigate parisitic capacities in your setup.

Remember that coaxial cable connecting your meter to your device could bring a large additional capacity (say more than 60pF/m). This geometry is the easiest to calculate. But if you try parallel wires you will find it is not much better. Keeping the wires far apart can only bring a limited improvement (look at the log in the formula). Keeping them short is certainly a good idea (10 cm could still bring 6pF !).

So, you are left to answer some essential questions:

how can you reduce the parasitic capacities
how could you eventually compensate them by a special arrangement
(zeroing the parasitic capacity somehow)
how you could reliably correct for them by some calibration (small corrections ...)
could you increase the tested capacity to reduce the parasitic effects
how did the fathers in the 19th century perform these measurements​

I have no answer right now for you. But I think this is basic electrical metrology and you could find the answers is appropriate handbooks. Let us know about your findings. I will do it too if I find something.

Michel
 
Last edited:
Hi,

For measuring the capacitance of the arrangment I am using a commercially avaliable capacitance meter, see http://www.farnell.com/datasheets/24173.pdf"

This has a 'zero-adjust' which allows my to 'zero' out leads between connecting them from the meter to the plates. On the 200pF range setting which I have the meter set for these experiments, an 820Hz excitation voltage is produce by the meter, but this should be of no concern to me right? because the meter takes all this into account when it produces the reading?

This should answer 'bystanders' question:
How are you doing the measurement?

and hopefully the first two of michels

how can you reduce the parasitic capacities
how could you eventually compensate them by a special arrangement
(zeroing the parasitic capacity somehow)



I will continue to look at various measurement techniques.
Any further help in resolving the matter will be greatly appreciated.

Regards

Tom
 
Last edited by a moderator:
Tom,

You should be absolutely sure that your meter and your method are reliable. Make some tests with a known capacity in situations (cables, connectors, ...) as close as possible to your setup. If such tests are not reliable, try other devices and methods.

Additionaly, I also express some doubt on the possiblity to cancel properly parasitic capacities that are much larger than the capacity you would try to measure. Therefore, you should certainly minimize these unwanted capacities as much as possible. For those parasitic capacities that you cannot remove, you should investigate for the best possible cancellation technique: I doubt that the built-in zeroing mechanism of your meter could eliminate accurately 50 pF when you try to measure 1 pF. I am confident that this is possible.

Michel
 
The zeroing mechanism is in the form of an adjustment knob which is manipulated by the user.

Tom
 
Tom,

The following link explains some practical problems when measuring capacities as you were:

http://www.gyogyitokezek.hu/fe/capresist.htm​

Maybe this will help you improve your experiment,

Michel
 
Last edited by a moderator:
  • #10
You're probably measuring parasitic capacitance from your cables/leads. Testing a known, commercial capacitance (e.g., Radio Shack) that has a similar C is a good idea.

I've measured parasitic C as high as 50pF in my high speed coaxs. It will help if you make the leads as short as possible, and remove as much stray metal/wires/etc. as possible.
 

Similar threads

  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 6 ·
Replies
6
Views
7K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 15 ·
Replies
15
Views
2K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 19 ·
Replies
19
Views
3K
  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 4 ·
Replies
4
Views
5K
Replies
4
Views
2K