- #1
Lancelot59
- 646
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Hi there. The book doesn't have an answer in the back for this problem, so I wanted to know if I was setting everything up correctly.
I need to find the area enclosed by r=1-sin(theta) but outside r=1. This is polar by the way. So a nice simple cardioid and circle. I decided to only do half and then double it, because of the symmetry.
Here is the integral I got.
[tex]
2*\frac{1}{2}[\int_{\frac{-\pi}{2}}^{0}{(1-sin(\theta))^{2} d\theta} - \int_{\frac{-\pi}{2}}^{0}{(1)} d\theta}]
[/tex]
My answer was [tex]\frac{5\pi}{2}+\frac{9}{2}[/tex]. I'm fine with integrating, I'm just wondering if I set it up correctly.
I need to find the area enclosed by r=1-sin(theta) but outside r=1. This is polar by the way. So a nice simple cardioid and circle. I decided to only do half and then double it, because of the symmetry.
Here is the integral I got.
[tex]
2*\frac{1}{2}[\int_{\frac{-\pi}{2}}^{0}{(1-sin(\theta))^{2} d\theta} - \int_{\frac{-\pi}{2}}^{0}{(1)} d\theta}]
[/tex]
My answer was [tex]\frac{5\pi}{2}+\frac{9}{2}[/tex]. I'm fine with integrating, I'm just wondering if I set it up correctly.
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