- #1
hoseA
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Hint: Consider the wheel's energy.
Consider a wheel of radius 1.23 m, mass
7.7 kg and moment of inertia I =1/2 MR^2
(it's a solid disk). The wheel rolls without
slipping in a straight line in an uphill direction 30 degrees above the horizontal. The wheel starts at angular speed 16.1 rad/s but the ro-
tation slows down as the wheel rolls uphill,
and eventually the wheel comes to a stop and
rolls back downhill.
The acceleration of gravity is 9.8 m/s^2
How far does the wheel roll in the uphill
direction before it stops? Answer in units of
m.
This is what I plan to do:
1. Use:
1/2 Iw^2 +1/2 mv^2 = mgh
by substituting Rw for v and solving for h.
2. "h" would equal the "y" component so I would then go on to use trig. to find the hypontenuse.
Would that work?
Consider a wheel of radius 1.23 m, mass
7.7 kg and moment of inertia I =1/2 MR^2
(it's a solid disk). The wheel rolls without
slipping in a straight line in an uphill direction 30 degrees above the horizontal. The wheel starts at angular speed 16.1 rad/s but the ro-
tation slows down as the wheel rolls uphill,
and eventually the wheel comes to a stop and
rolls back downhill.
The acceleration of gravity is 9.8 m/s^2
How far does the wheel roll in the uphill
direction before it stops? Answer in units of
m.
This is what I plan to do:
1. Use:
1/2 Iw^2 +1/2 mv^2 = mgh
by substituting Rw for v and solving for h.
2. "h" would equal the "y" component so I would then go on to use trig. to find the hypontenuse.
Would that work?
