Ambiguity in part B -- Rocket engine failure....

AI Thread Summary
The discussion centers on the ambiguity in Part B of a physics problem regarding a rocket's engine failure and its subsequent descent. Participants express confusion over whether the question asks for the time until the rocket reaches maximum height or the time until it crashes back to the launch pad after engine failure. There is a consensus that the wording could be clearer, with suggestions that using "onto" instead of "before" would eliminate confusion. Despite solving the problem, the phrasing remains a point of frustration for users. Clarity in problem statements is essential for accurate understanding and resolution.
Fancypen
Messages
25
Reaction score
6
Member advised to use the homework template for posts in the homework sections of PF.
Question: A 7750 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s^2 and feels no appreciable air resistance. When it has reached a height of 555 m , its engines suddenly fail so that the only force acting on it is now gravity.

Part B: How much time after engine failure will elapse before the rocket comes crashing down to the launch pad?

So, I understood Part B to mean: calculate the time from 555 m, when the engines fail, to the max height, when velocity=0. However, they are looking for the time from when the engines shuts off, 555 m, to when it crashes.

I feel like Part B is ambiguous... we use MasteringPhysics and the book is great, but it seems like it was written in a lazy way. Maybe it's just me.

What do you think?
 
Physics news on Phys.org
Fancypen said:
Question: A 7750 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s^2 and feels no appreciable air resistance. When it has reached a height of 555 m , its engines suddenly fail so that the only force acting on it is now gravity.

Part B: How much time after engine failure will elapse before the rocket comes crashing down to the launch pad?

So, I understood Part B to mean: calculate the time from 555 m, when the engines fail, to the max height, when velocity=0. However, they are looking for the time from when the engines shuts off, 555 m, to when it crashes.

I feel like Part B is ambiguous... we use MasteringPhysics and the book is great, but it seems like it was written in a lazy way. Maybe it's just me.

What do you think?

p.s. I already solved the problem, but this wording is bothering me!
 
Fancypen said:
p.s. I already solved the problem, but this wording is bothering me!
I agree it's unclear. Had it said "onto" the launch pad there would be no ambiguity.
 
  • Like
Likes Fancypen
haruspex said:
I agree it's unclear. Had it said "onto" the launch pad there would be no ambiguity.

Okay, thank you!
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top