Amplitude of a block oscillating on a spring

AI Thread Summary
The discussion focuses on calculating the amplitude of a block oscillating on a spring, given its mass, spring constant, initial elongation, and speed. The user initially calculates the angular frequency and attempts to find amplitude but arrives at an incorrect value. A key point raised is that the initial elongation of 0.15 m is not the maximum displacement, and the speed of 3 m/s is not the maximum speed. The suggestion is to calculate the total mechanical energy to determine the correct maximum speed and subsequently find the amplitude. The correct amplitude is identified as 0.18 m.
drunknfox
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Homework Statement


a .25kg block oscillates on the end of a spring with a spring constant of 200N/m. If the oscillation is started by elongating spring to 0.15m and giving the block a speed of 3.0m/s. The amplitude is?


Homework Equations


omega= sqrt(k/m), Vm = (omega)Xm


The Attempt at a Solution



omega= sqrt (200/.25) = 28.28 (3m/s) = 28.28Xm (3/28.28) = .106

The correct answer is .18m..what am i missing?
 
Physics news on Phys.org
The spring is stretched by 0.15 m and the block has 3 m/s speed at the same time. 0.15 is not the maximum displacement and 3 m/s is not the maximum speed. Calculate the energy, and get the maximum speed from it.

ehild
 
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