An 1520 kg car is moving to the right at a constant velocity of 2.94 m/s.

AI Thread Summary
The car, weighing 1520 kg and moving at a constant velocity of 2.94 m/s, experiences no net force, as constant velocity indicates zero acceleration. This applies regardless of the direction of movement; whether to the right or left, the net force remains zero. The discussion clarifies that the formula Force = Mass * Acceleration is applicable, but since acceleration is absent, the net force is confirmed to be zero in both scenarios. Understanding that constant velocity equates to no net force simplifies the problem. Overall, the key takeaway is that a car moving at constant velocity has a net force of zero, independent of its direction.
Fanjoni
Messages
11
Reaction score
0
An 1520 kg car is moving to the right at a constant velocity of 2.94 m/s.

(a) What is the net force on the car?
(b) What would be the net force on the car if it were moving to the left?

any help i tried using Force=Mass*Acceleration
I also don't know what it wants me to dod when it asks when it moves to the left?
 
Physics news on Phys.org
A constant velocity means that no acceleration exists. If no acceleration exists, then the sum of the forces must be zero (in both cases). Doesn't matter what direction the car is going; if it isn't accelerating, then the net force is 0.
 
Oh it was that easy. I was kinda thinking to hard

Thanks BishopUser
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top