An expression equivalent to [cos(x)+sin(x)]/[cos(x)+sin(x)]

[aisha]

I have this question --> \frac {\cos (x) + \sin (x)} {\cos (x) - \sin (x)} how do you find an expression that is eqivalent to this using trig identities? I have no clue every time I do this problem the top and bottom cancel out plus none of the terms can be replaced with trig identities, can somone please help me out ?

 

[Galileo]

You could multiply the top and bottom by cos x+sin x.
Then use some trig identities like \sin^2x+\cos^2x=1 upstairs and downstairs. Then you can simplify is further by using 2 other trig id's.
Look up the table. :)

 

[aisha]

You could multiply the top and bottom by cos x+sin x.
Then use some trig identities like \sin^2x+\cos^2x=1 upstairs and downstairs. Then you can simplify is further by using 2 other trig id's.
Look up the table. :)

Can I ask what table?

 

[xanthym]

Try what the previous msg suggested:
a) Multiply Numerator & Denominator by:
cos(\theta) + sin(\theta)
b) Use Identities Like:
sin^2(\theta) + cos^2(\theta) = 1
sin(2\theta) = 2sin(\theta)cos(\theta)
cos(2\theta) = cos^2(\theta) - sin^2(\theta)
Also check the following Trig Identity Table:
http://www.math2.org/math/trig/identities.htm

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[primarygun]

why not try tan ?

 

[xanthym]

Yes. The tan() and sec() would be next. (Needed to leave something for the reader to discover!)

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