Calculators An integral my Ti-89 refused to do

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The discussion revolves around the evaluation of the indefinite integral of sin(x)/(1+x^2)dx over the interval from -1 to 1. It is suggested that the integral can be simplified by breaking it into two parts: from -1 to 0 and from 0 to 1. A change of variable, specifically x to -x, is recommended for the left half of the integral, which demonstrates that the two areas under the curve cancel each other out due to symmetry. Consequently, the integral evaluates to zero because the contributions from both halves are equal in magnitude but opposite in sign. Graphing the function from -1 to 1 supports this conclusion, showing that the regions reflect across the origin.
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Homework Statement



Indefinite integral of sin(x)/(1+x^2)dx


Homework Equations





The Attempt at a Solution

 
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What reason do you have to believe that has an indefinite integral that can be written in terms of elementary functions?
 
HallsofIvy said:
What reason do you have to believe that has an indefinite integral that can be written in terms of elementary functions?

i m sorry i don't really comprehend what you are trying to say here.

By the way my mistake on my behalf, it is the integral between the interval of -1 and 1

I don't know how to get started
 
This question has a very simple answer. Try graphing the function from -1 to 1 and you might see it.
 
i realized that in the first place, but is there a mathematical manipulation that could get the result?
 
Break the integral up into integrals from -1 to 0 and from 0 to 1. In the first, make a change of variable, x -> -x.
 
Avodyne said:
Break the integral up into integrals from -1 to 0 and from 0 to 1. In the first, make a change of variable, x -> -x.

i don't understand what you are saying >.<

i started calc this year.

Could you show me your steps really quick
 
First tell me what the value of the integral is, and give your best explanation.
 
according to the graph it's 0 because the line is reflected on the origin so the two regions canceled each other out.
 
  • #10
Yes, exactly. So the integral over the left half (from -1 to 0) must equal minus the integral over the right half (from 0 to 1).

Do you know how to change variables in an integral? You want to change the variable in the left-half integral from x to -x, and then show that the result is equal to minus the right-half integral.
 

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