An Interval that is both open and closed.

  • Thread starter Thread starter heshbon
  • Start date Start date
  • Tags Tags
    Closed Interval
heshbon
Messages
27
Reaction score
0

Homework Statement


Let I C R be an interval which is open and closed at the same time. Prove that I=R or I is the empty set.


Homework Equations





The Attempt at a Solution



I'm looking more for a outline structure for the solution. I have made assumptions that I is not equal to R seeking a contradition, but i don't know what further assumptions to make.
 
Physics news on Phys.org
A closed set is one that contains all of its boundary points. An open set is one that contains none of its boundary points.

In order to be both open and closed, a set must contain all of its boundary points and none of its boundary points!

If "all boundary points" is the same as "no boundary points", what can you say about the boundary points of the set?
 
Well, the boundry point can't be real.., maybe i can say that the set is unbounded
 
If a set has NO boundary points the "all boundary points" is the same as "no boundary points". A set is both open and closed if and only if it has no boundary points. What are the boundary points of the empty set? What are the boundary points of R?

(A point, p, is a boundary point of set, S, if and only if every neighborhood of p contains points of both A and the complement of S.)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top