How Can You Calculate Ball Trajectory and Impact Velocity?

AI Thread Summary
To calculate the ball's trajectory and impact velocity, the initial conditions include a launch height of 256 feet and an initial velocity of 160 ft/sec. The ball reaches a maximum height of 400 feet after 5 seconds. To determine the speed at t=3 seconds, the change in distance over time must be calculated, but the distance at that moment is unclear. The velocity just before impact can be found using displacement and acceleration, considering the total distance fallen from the maximum height plus the building height. The total time in the air is the sum of the ascent and descent times, which can be derived from the known parameters.
imfunsize2011
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Homework Statement


A ball is fired vertically upward from the top outside ledge of a 256ft high building with an initial velocity of 160ft/sec. Assue lgl=32.0 ft/sec^2.

Homework Equations


What is the speed of the ball at t=3 seconds?
and
What is the velocity of the ball just before it hits the ground at the base of the building?
and
What was the total time the ball was in the air?

The Attempt at a Solution


it takes the ball 5secs to hit the max point of trajectory, the ball goes 400ft upward,

to find speed you have take the change in distance/ change in time. the time would be 3-0 but the distance is where I am stuck.

to find the velocity of the ball just before it hits ground. you take the change in displacement/change in time, but what is the time

the totall time it is in the air, i am totally lost on
 
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V = distance/time is nice for calculating the AVERAGE velocity of an object over some distance. However, the average velocity is not what the question asks for. The question asks for the instantaneous velocity of the object just before it hits the ground. You need to find a different equation that will help you calculate the instantaneous velocity of an object undergoing a constant acceleration.
 
imfunsize2011 said:

Homework Statement


A ball is fired vertically upward from the top outside ledge of a 256ft high building with an initial velocity of 160ft/sec. Assue lgl=32.0 ft/sec^2.

Homework Equations


What is the speed of the ball at t=3 seconds?
and
What is the velocity of the ball just before it hits the ground at the base of the building?
and
What was the total time the ball was in the air?

The Attempt at a Solution


it takes the ball 5secs to hit the max point of trajectory, the ball goes 400ft upward,

to find speed you have take the change in distance/ change in time. the time would be 3-0 but the distance is where I am stuck.

to find the velocity of the ball just before it hits ground. you take the change in displacement/change in time, but what is the time

the totall time it is in the air, i am totally lost on

Welcome to PF.

It's best to focus on answering the questions they ask, but it's good that you know how to find those things.

For a) you know how to find the time to max height, so why can't you figure what happens after 3 seconds with whatever equation you used to find 5 sec?

For b, Figure the max height. You did determine it goes up 400 ft. So how long does it take to drop to the ground below - 400 + 256 below? And how fast will it be going when it does? You know distance and acceleration.

Here are some formulas you might ind useful.
https://www.physicsforums.com/showpost.php?p=905663&postcount=2

Your observations on distance and time are going to be that useful in answering the questions they ask because they want to know instantaneous v.

For c) time up + time down = total time. You have half of it already.
 
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