Analyzing Current in a Branch: Using KCL and KVL

  • Thread starter Thread starter Jahnavi
  • Start date Start date
  • Tags Tags
    Branch Current
AI Thread Summary
The discussion centers on finding the current through a 5Ω resistor using Kirchhoff's Current Law (KCL) and Kirchhoff's Voltage Law (KVL). Participants clarify that the leftmost 1A represents a current source, not a galvanometer. One user arrives at the conclusion that the current i equals 0, which is confirmed by others. The use of KCL and KVL is emphasized, with suggestions to also apply the node voltage method for accuracy. Overall, the conversation highlights the importance of understanding circuit components and methods for solving current in electrical circuits.
Jahnavi
Messages
848
Reaction score
102

Homework Statement


current.jpg

Q . Find current i through the 5Ω resistor ?

Homework Equations

The Attempt at a Solution



I would like to understand what does leftmost 1A represent . I haven't seen something like that before in my book . Is it a Galvanometer or something else ?
 

Attachments

  • current.jpg
    current.jpg
    13.4 KB · Views: 801
Physics news on Phys.org
Jahnavi said:

Homework Statement


View attachment 222760
Q . Find current i through the 5Ω resistor ?

Homework Equations

The Attempt at a Solution



I would like to understand what does leftmost 1A represent . I haven't seen something like that before in my book . Is it a Galvanometer or something else ?
It is a current source.
 
  • Like
Likes Jahnavi
gneill said:
It is a current source.

OK .

I am getting option d) i = 0 . Is that correct ?
 
Jahnavi said:
OK .

I am getting option d) i = 0 . Is that correct ?
You'll have to show the details of your work. We won't just confirm or deny what could potentially be a guess :smile:
 
Jahnavi said:
OK .

I am getting option d) i = 0 . Is that correct ?
That is correct.

Btw, you can check it yourself using node voltage method and KCL.
 
  • Like
Likes Jahnavi
cnh1995 said:
you can check it yourself using node voltage method and KCL.

I did use KCL and KVL to arrive at the result .Using the current source and KCL , I assigned current in all the resistors . Then I wrote 2 KVL eqns. for the upper and bottom right loop .

Thanks a lot :smile:
 
Jahnavi said:
I did use KCL and KVL to arrive at the result .Using the current source and KCL , I assigned current in all the resistors . Then I wrote 2 KVL eqns.

Thanks a lot :smile:
Well done!
I myself prefer the node voltage method to avoid any silly mistakes while writing KVL.
 
  • Like
Likes Jahnavi
Back
Top