Analyzing Forces in an Electrically Charged Pendulum Experiment

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In the electrically charged pendulum experiment, a 1.10 g plastic ball is suspended by a 59.0 cm string and swings to a 19-degree angle when a charged rod is brought near. The forces acting on the ball include gravitational force, tension in the string, and the horizontal electric force. The correct equations for the vertical and horizontal components are mg = Tcos(19) and F = Tsin(19), respectively. After calculations, the tension was found to be 0.0114 N and the electric force was determined to be 0.0037 N. The experiment highlights the importance of considering both vertical and horizontal forces in analyzing the system.
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In an electricity experiment, a 1.10 g plastic ball is suspended on a 59.0 cm long string and given an electric charge. A charged rod brought near the ball exerts a horizontal electrical force F on it, causing the ball to swing out to a 19 degree angle and remain there.



What is the magnitude of F?
What is the tension in the string?




Ok, I set up my free body diagram and set the forces along the y-axis = 0.
I came up the the equation, .1078cos(19) + F -mg=0 , which does not give me the right magnitude for F, what is wrong with my equation? The length of the string is only needed for the tension part of problem correct? But I do not know how to set that up either.
 
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Well vertically you have:
mg = Tcos19

And horizontally:
F = Tsin19

So I'd find the tension first, then use that to find the electrostatic force on the ball.
 
this isn't really what id call my good point in physics but i would say that you mite need to use the length of the string for more then just the tension.. set up ur thingo with various lengths of cord and check the differences... this probably didnt help u much but as i said,,, not my good point
 
Ok so I came up with T=.0114 and F=.0037N, which is correct. Thank you!
 
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