+ and - voltages from a battery

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It is possible to generate both positive and negative voltages from a 9V battery using a circuit that includes an oscillator, such as a pulse-generating microcontroller or IC. By placing two identical resistors in series, the middle connection can serve as a ground reference, allowing for +4.5V and -4.5V outputs. For higher voltage differences, capacitors and step-up circuits can be utilized. A push-pull arrangement with two output stages can create an 18V peak-to-peak signal, commonly used in audio amplifiers powered by 12V batteries. The frequency of the output signal in a circuit using an LM555 timer is influenced by the capacitor and resistor values.
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Is it possible to use a 9v battery and run it through some circuit or system to get a squarewave output that has a positive and negative voltage. Ideally the two voltages would be the same but the negative of the other.
 
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Of course it's possible, but it's not simple. At the most basic level, it would require an oscillator.

Since all voltages are relative, you could easily put two identical resistors in series between your two supply terminals, and call the middle connection "0", and the other two connections "+4.5" and "-4.5". You can increase the absolute voltage difference using capacitors and step-up circuits.

The short, practical answer is to use the +9V as a power supply to a pulse-generating microcontroller or IC, and also as a power supply to some amplifiers which change it's output to whatever voltages you need.
 
Thanks for your reply. So I found this circuit setup that seems to do what I am looking for. here is the link. http://www.555-timer-circuits.com/bi-polar-led-driver.html It uses the LM555 timer, the only thing I'm not sur of is what the freuency of the switching light would be. Would that be determined by the capacitor and 33K resistor or is it more complicated than that?
 
If you want a 18V peak to peak signal and you are prepared to 'float' your supply or the destination signal (say you want to feed a transformer or loudspeaker) you can use two 'output stages' operating in antiphase, the two 9V squarewaves will have a peak difference of 18V.
This 'push - pull" arrangement was common in audio amplifiers, powered with 12V car batteries. You get 4 times the peak power this way into a given load.
 
Very basic question. Consider a 3-terminal device with terminals say A,B,C. Kirchhoff Current Law (KCL) and Kirchhoff Voltage Law (KVL) establish two relationships between the 3 currents entering the terminals and the 3 terminal's voltage pairs respectively. So we have 2 equations in 6 unknowns. To proceed further we need two more (independent) equations in order to solve the circuit the 3-terminal device is connected to (basically one treats such a device as an unbalanced two-port...
suppose you have two capacitors with a 0.1 Farad value and 12 VDC rating. label these as A and B. label the terminals of each as 1 and 2. you also have a voltmeter with a 40 volt linear range for DC. you also have a 9 volt DC power supply fed by mains. you charge each capacitor to 9 volts with terminal 1 being - (negative) and terminal 2 being + (positive). you connect the voltmeter to terminal A2 and to terminal B1. does it read any voltage? can - of one capacitor discharge + of the...

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