- #1
gap0063
- 65
- 0
Homework Statement
An m2 = 1.2 kg can of soup is thrown upward with a velocity of v2 = 4.6 m/s. It is immediately struck from the side by an m1 = 0.63 kg rock traveling at v1 = 7.9 m/s.
The rock ricochets off at an angle of α = 65◦ with a velocity of v3 = 5.5 m/s.
(a)What is the angle of the can’s motion after the collision?
Answer in units of ◦.
(b)With what speed does the can move immediately after the collision?
Answer in units of m/s.
Homework Equations
Px=m1v3cos[tex]\alpha[/tex]+m2v4cos[tex]\beta[/tex]
Py=m1v3sin[tex]\alpha[/tex]+m2v4sin[tex]\beta[/tex]
where Px= m1v1
and Py=0
The Attempt at a Solution
so then I solved for v4= -m1v3sin[tex]\alpha[/tex]/m2sin[tex]\beta[/tex]
then I plugged v4 back into the first equation and I think this is where I messed up, probably in the algebra because then:
m1v1= m1v3cos[tex]\alpha[/tex]+m2(m1v3sin[tex]\alpha[/tex]/m2sin[tex]\beta[/tex])cos[tex]\beta[/tex]
m1v1= m1v3cos[tex]\alpha[/tex]-(m1v3sin[tex]\alpha[/tex]cos[tex]\beta[/tex]
then I plugged numbers in:
4.977= 3.465 cos 65[tex]\circ[/tex]-3.14036 cot [tex]\beta[/tex]
3.14036cot[tex]\beta[/tex]=-3.51263
[tex]\beta[/tex]=137.203[tex]\circ[/tex]
as for part (b) I don't know how to solve without part (a)