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Angle between the incident ray and the reflected ray?

  1. Feb 22, 2005 #1
    A ray of light strikes a mirror at an angle of 53 degrees to the normal.

    A) what is the angle of reflection?
    Ans: 53 degrees

    B) what is the angle between the incident ray and the reflected ray?
    Ans: 53+53 = 106 degrees

    C) A ray of light has an angle of incidence of 30 degres on a block of quartz and an angle of refraction of 20 degrees. What is the index of refraction for this block of quartz?
    Ans: Nr = (1.54) (sin 30) / (sin20) = 2.25

    are the above answers correct?

    thanks
     
    Last edited: Feb 22, 2005
  2. jcsd
  3. Feb 22, 2005 #2
    Where did the 1.54 com from in:?
    "Nr = (1.54) (sin 30) / (sin20) = 2.25"
    Is the light ray in air before it hits the quartz? I am assuming so. So one of your indexes of refraction in the above equation should be 1 since 1 is the index of refraction of air.
     
  4. Feb 22, 2005 #3
    but.... dont i have to specify the index of refraction of quartz which is 1.54..... i dont see where the index of refraction of air would fit in..

    EDIT: nevermind figured it out... so basically it'll be Nr= sin 30/sin20?
     
    Last edited: Feb 22, 2005
  5. Feb 22, 2005 #4
    Yes that looks good with the edit
     
  6. Feb 22, 2005 #5
    great.. thanks much :)
     
  7. Feb 23, 2005 #6
    No problem and thank you for the response at the end it is nice to know that I helped.
     
  8. Feb 23, 2005 #7

    HallsofIvy

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    The problem ASKED for the index of refraction of quartz! Actually there are different kinds of quartz that have slightly varying indices of refraction. Since sin(30)/sin(20)= 1.46, that's not too far off your value.
     
  9. Feb 23, 2005 #8
    Yeah I looked it up. It think this type of quartz is Fused quartz, do either of you know the difference between fused quartz and just plain old quartz?
     
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