- #1
bamalam
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HELP! I keep getting a solution that is not part of the choices. Where am I messing up?
A grindstone, originally rotating at 126 rad/s undergoes a constant angular acceleration so that it makes 20.0 rev in the first 8.00s. What is the angular acceleration?
a) 0.313 rad/s2
b) 0.625 rad/s2
c) 2.50 rad/s2
d) 1.97 rad/s2
e) 13.79 rad/s2
My Calculations:
20rev*2PIrad/rev = 40PI rad = theta
t = 8 sec
wo = 126 rad/sec
theta = wo*t+1/2*a*t^2
40PI = 126*8+.5*a*8^2
40PI-126*8 = 32a
a = -27.57 rad/sec^2
A grindstone, originally rotating at 126 rad/s undergoes a constant angular acceleration so that it makes 20.0 rev in the first 8.00s. What is the angular acceleration?
a) 0.313 rad/s2
b) 0.625 rad/s2
c) 2.50 rad/s2
d) 1.97 rad/s2
e) 13.79 rad/s2
My Calculations:
20rev*2PIrad/rev = 40PI rad = theta
t = 8 sec
wo = 126 rad/sec
theta = wo*t+1/2*a*t^2
40PI = 126*8+.5*a*8^2
40PI-126*8 = 32a
a = -27.57 rad/sec^2