Angular acceleration of a softball

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SUMMARY

The discussion focuses on calculating the angular acceleration of a softball during the "windmill" pitching method. An experienced pitcher can achieve a pitch speed of 89.0 mph (39.783 m/s) with an angular speed of 8.4310 rev/s. The distance from the shoulder joint to the ball is 75.1 cm. To find the angular acceleration, one must use the equations of angular motion kinematics, which are analogous to linear kinematics.

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One method of pitching a softball is called the "windmill" delivery method, in which the pitcher's arm rotates through approximately 360° in a vertical plane before the 198 gram ball is released at the lowest point of the circular motion. An experienced pitcher can throw a ball with a speed of 89.0 mi/h. Assume that the angular acceleration is uniform throughout the pitching motion, and take the distance between the softball and the shoulder joint to be 75.1 cm.

I found 89mph= 39.783m/s and the angular speed to be 8.4310rev/s. How do I find the angular acceleration from this?
 
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physics1234 said:
One method of pitching a softball is called the "windmill" delivery method, in which the pitcher's arm rotates through approximately 360° in a vertical plane before the 198 gram ball is released at the lowest point of the circular motion. An experienced pitcher can throw a ball with a speed of 89.0 mi/h. Assume that the angular acceleration is uniform throughout the pitching motion, and take the distance between the softball and the shoulder joint to be 75.1 cm.

I found 89mph= 39.783m/s and the angular speed to be 8.4310rev/s. How do I find the angular acceleration from this?
You will want the angular speed to be in radians per second. You need to use the equations of angular motion kinematics. These are directly analogous to the more familiar equations of linear kinematics

http://online.cctt.org/physicslab/content/PhyAPC/lessonnotes/rotationalmotion/kinematics.asp
 

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