Angular acceleration of the disk as a function of time

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SUMMARY

The discussion centers on the angular acceleration of a disk as a function of time, specifically a disk with a radius of 21.0 cm. The acceleration of a ball attached to the disk follows the equation a(t) = At, where A is determined to be 0.533 m/s². The angular acceleration of the disk is expressed as 2.54 rad/s³(t), and the time taken to reach an angular speed of 12.0 rad/s is calculated to be 3.07 seconds. The participant successfully resolved the problem after initially struggling with part d.

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Homework Statement


A disk of radius 21.0cm is free to turn about an axle perpendicular to it through its center. It has very thin but strong string wrapped around its rim, and the string is attached to a ball that is pulled tangentially away from the rim of the disk (the figure ). The pull increases in magnitude and produces an acceleration of the ball that obeys the equation a(t)=At, where t is in seconds and A is a constant. The cylinder starts from rest, and at the end of the third second, the ball's acceleration is 1.60m/s^2 .

A) find A
B)Express the angular acceleration of the disk as a function of time.
c)How much time after the disk has begun to turn does it reach an angular speed of 12.0rad/s
Through what angle has the disk turned just as it reaches 12.0rad/s ? (Hint: See Section 2.6 in the textbook.)


Homework Equations



i solved a, b, &c, I'm stuck on part d

The Attempt at a Solution


for A, i got 0.533m/s^2, b)2.54rad/s^3(t), c)3.07s, d)?
for part d, I'm clueless on which formula to use
 
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NVM, i figured it out
 

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