Angular Frequency Change with Mouse Movement on Wagon Wheel

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The discussion centers on a physics problem involving a mouse riding on a rotating wagon wheel. Initially, the wheel has an angular frequency of 1.00 revolutions per second, and the mouse's mass is 0.1 kg. When the mouse moves to the center of the wheel, the conservation of angular momentum must be considered to determine the new angular frequency. Participants emphasize the importance of recognizing that angular momentum is conserved in this scenario. The key takeaway is that the new angular frequency can be calculated using the initial conditions and the conservation principle.
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Homework Statement



a mouse is rinding on the rim of a 2.0kg wagon wheel that rotates freely in a horizontal plane at an angular frequency of 1.00 revs/sec. after riding there for a while, the mouse runs into the center, axis, of the wheel. the mass of mouse is 0.1kg and assume that all of the mass of the wheel is concentrated around the rim. what is the new angular frequency when the mouse reaches the axis?

Homework Equations


ok i know that \omega is directly proportional to the freq. which is the angular frequency.
\omega=2(pi)/T


The Attempt at a Solution


using the equation for omega, 2(pi)/1 equals 6.28319. is that my new angular freq.? i don't understand what to use?
 
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hint: what quantity is conserved in the problem?
 
i don't understand what is concerved? heeeeeeeelllp? lol
 

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