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A swing bridge has to be turned through a right angle in 120 seconds. The first 50.4 seconds is a period of uniform angular acceleration ; the subsequent 34.8 seconds is a period of uniform angular velocity and the third period of 34.8 seconds is a period of uniform angular retardation. Input your answers to five decimal places when appropriate, and find
the angular displacement that occurred during time period two, (0%) rads
the angular displacement in time period three
the angular acceleration of the bridge , (0%) rads/sec2
the maximum angular velocity (0%) rads/sec
the retardation
Answers:0.706±0.05 rads, 0.353±0.05 rads, 4E-4±1E-4 rads/sec2,0.0202±0.01 rads/sec
-6E-4±1E-4 rads/sec2
Doing some revision and can't work out how to get answers, Tried to write angular displacement in terms of period 2 but can't figure out how to do that
Thanks
the angular displacement that occurred during time period two, (0%) rads
the angular displacement in time period three
the angular acceleration of the bridge , (0%) rads/sec2
the maximum angular velocity (0%) rads/sec
the retardation
Answers:0.706±0.05 rads, 0.353±0.05 rads, 4E-4±1E-4 rads/sec2,0.0202±0.01 rads/sec
-6E-4±1E-4 rads/sec2
Doing some revision and can't work out how to get answers, Tried to write angular displacement in terms of period 2 but can't figure out how to do that
Thanks