Angular momentum; flying motorcycle

AI Thread Summary
The discussion focuses on calculating the horizontal acceleration needed for a motorcycle's front wheel to lift off the ground, given specific dimensions and conditions. The center of mass is located 88.0 cm above the ground and halfway between the wheels, with the distance between the wheel centers being 155 cm. Participants discuss using torque equations, specifically Στ = Iα and τ = r x F, to analyze the forces acting on the motorcycle. One user suggests placing the axis of rotation at the rear wheel's contact point to simplify calculations. Ultimately, the user reports finding the solution after considering the forces at play.
MrRice5555
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Homework Statement


The distance between the centers of the wheels of a motorcycle is 155 cm. The center of mass of the motorcycle, including the biker, is 88.0 cm above the ground and halfway between the wheels. Assume the mass of each wheel is small compared with the body of the motorcycle. The engine drives the rear wheel only. What horizontal acceleration of the motorcycle will make the front wheel rise off the ground?

Homework Equations


\Sigma \tau= I \alpha
\tau = r x F

The Attempt at a Solution


I don't know how to even start this. I drew a diagram, and tried to sum the torques by placing the axis of rotation at the center of the rear wheel. Have no idea what to do from there.
 
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Try putting your center of rotation at the point where the rear wheel touches the ground. What are the forces acting on the center of gravity?
 
OH I see there's a force applied from the engine as well as the weight of the engine. I believe I got the answer. Thanks!
 

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