Angular Momentum (train on a track)

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The discussion revolves around calculating the angular speed of a wheel with a toy train on a track. The system consists of a wheel and track with a combined mass of 3.59 kg and a radius of 1.79 m, while the train has a mass of 0.203 kg and moves at a steady speed of 0.551 m/s. To find the angular speed of the wheel, the principle of conservation of angular momentum is applied, equating the linear momentum of the train to the angular momentum of the wheel. The equation used is mv = MV, where m is the mass and v is the velocity of the train, and M is the mass and V is the angular speed of the wheel. This approach allows for the determination of the wheel's angular speed based on the given parameters.
bosco3234
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Can someone help with this? Thnx

A toy train track is mounted on a large wheel that is free to turn with negligible friction about a vertical axis as shown in the figure above. The mass of the wheel plus track is 3.59 kg and the radius is 1.79 m. Ignore the mass of the spokes and hub. A toy train of mass 0.203 kg is placed on the track and, with the system initially at rest, the electric power is turned on. The train reaches a steady speed of 0.551 m/s with respect to the track. What is the angular speed of the wheel?
 
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Equate mvr of the train to mvr of the track. Since r is the same for each, just set mv=MV.
 
Thanks much
 

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