A uniform thin rod (mass 2.74 kg, length 0.934 m) lies motionless on a frictionless, horizontal table. The rod is free to move in any direction on the table. A small block (a point particle of mass = 0.621 kg) slides across the table, moving at right angles to the rod, at speed 4.1 m/s. The block strikes the rod at a distance of 0.11 m below the center of mass, and stops. Assume the block does not stick to the rod
vf, the speed of the center of mass of the rod after the collision
The Attempt at a Solution
I used the conservation of angular momentum:
mvx=Iw: distance between the point of collison and the center of mass
then solve for V. But it does not seem to give me the right solution.