I'm kinda having trouble figuring out this problem...i already know that i have to use conservation of angular momentum Iiwi=Ifwf but i'm having trouble calculating the key part, the second moment of inertia. I'm pretty sure that im' supposed to be using this form of the calculation of inertia, I=Mr^2... but i still can't seem to solve it... like when i use it to test whether the numbers work out for the first moment of inertia 2.92 = 2.92*2 * 1.09^2, these numbers don't work out. A student sits on a freely rotating stool holding two weights, each of mass 2.92 kg. When his arms are extended horizontally, the weights are 1.09 m from the axis of rotation and he rotates with an angular speed of 0.746 rad/s. The moment of inertia of the student plus stool is 2.92 kg · m2 and is assumed to be constant. The student pulls the weights in horizontally to a position 0.307 m from the rotation axis. Question: Find the new angular speed and find the kinetic energy before and after he pulls the weight inward.