Angular speed uniform rod problem

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SUMMARY

The discussion centers on calculating the angular speed of a uniform rod with a length of 4.0 m, pivoting about a frictionless pin, released from an angle of 40° above the horizontal. The principle of conservation of energy is applied, where the potential energy at the initial position transforms into rotational kinetic energy as the rod passes through the horizontal position. The gravitational acceleration is considered to be 9.83 m/s², which is crucial for accurate calculations of energy transformation.

PREREQUISITES
  • Understanding of conservation of energy principles
  • Knowledge of rotational kinetic energy equations
  • Familiarity with gravitational acceleration effects
  • Basic concepts of angular motion
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  • Study the derivation of the conservation of energy equation in rotational dynamics
  • Learn how to calculate potential energy in gravitational fields
  • Explore the equations for rotational kinetic energy and their applications
  • Investigate the effects of pivot points on angular motion
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Homework Statement



The thin uniform rod in Fig. 10-52 has length 4.0 m and can pivot about a horizontal, frictionless pin through one end. It is released from rest at angle θ = 40° above the horizontal. Use the principle of conservation of energy to determine the angular speed of the rod as it passes through the horizontal position. Assume free-fall acceleration to be equal to 9.83 m/s2.



Homework Equations



i really have no idea where to start this :/

The Attempt at a Solution

 
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Well the question says to use the law of conservation of energy.

Since we are talking energy and rotation, rotational kinetic energy should be in your energy equation.


At the angle of 40 degrees, when just held at that position (such that it is at rest), what type of energy does it possess? When it passes through the horizontal plane, what type of energy does it have?
 
thanks for your help, i actually got it :)
 

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