Angular Velocity Calc: Cross-Shape Object, KE, MOI, Energy

AI Thread Summary
To find the angular velocity of the cross-shaped object, the correct formula to use is KE = 1/2 Iω^2, as the center of mass is not moving. The moment of inertia (I) is given as 1764 kgm², and the total kinetic energy (KE) is 4.2 J. Using these values, solve for angular velocity (ω) by rearranging the formula to ω = sqrt(2KE/I). Ensure that only the rotational kinetic energy is considered unless the center of mass is in motion. This approach will yield the correct angular velocity in radians per second.
jscherf92
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There is a cross shaped object with masses on each arm, the arms are different lengths and they are perpendicular to each other. the longer rod, (7m radius from center) has two 12kg masses, one on each end. The shorter rod (3.5m radius from center) has two 24kg masses one on each end. I=1764kgm^2. Total KE= 4.2J. I need to find angular velocity in radians/sec.

So far I am trying KE=1/2Iw^2+1/2mv^2 and i keep getting the wrong answer. Can anyone point me in the right direction?
 
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Hi jscherf92! :smile:

(have an omega: ω and try using the X2 tag just above the Reply box :wink:)

You can use 1/2 Iω2 or 1/2 mv2 but not both (unless the centre of mass is moving, in which case it's 1/2 Iω2 + 1/2 mvc.o.m2) :smile:
 
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