Angular Velocity On Pulley After Variable Force

AI Thread Summary
The discussion revolves around calculating the angular velocity of a pulley subjected to a time-varying tangential force. The force is defined as F = 0.50t + 0.30t², and the initial conditions state that the pulley starts from rest. Participants highlight the need to integrate the force function over the specified time interval to determine the torque and subsequently the angular acceleration. There is confusion regarding the multiplication by time in the initial calculations, which is corrected by emphasizing the integration of the force to find the net torque. Ultimately, the correct approach involves using the integral of the force to accurately compute the angular velocity after 4 seconds.
Jshumate
Messages
8
Reaction score
0

Homework Statement


A pulley having a rotational inertia of 1.1 10-3 kg·m2 about its axle and a radius of 23 cm is acted on by a force, applied tangentially at its rim, that varies in time as F = 0.50t + 0.30t2, where F is in Newtons and t in seconds. If the pulley was initially at rest, find its angular speed after 4.0 s.

Homework Equations


(I'm having trouble with Latex so excuse my non-greek)
T = AI
(net torque= angular acceleration*rotational inertia)
w = at
(angular velocity = angular acceleration*time)
T = rF
(torque = length*force)


The Attempt at a Solution


w = (T)(t)/I
rFt/I = w

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s

But this is incorrect. I am not sure how to handle this with the variable force being applied.
 
Physics news on Phys.org
Jshumate said:

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s


why did you multiplied by the time?

ehild
 
Jshumate said:

Homework Statement


A pulley having a rotational inertia of 1.1 10-3 kg·m2 about its axle and a radius of 23 cm is acted on by a force, applied tangentially at its rim, that varies in time as F = 0.50t + 0.30t2, where F is in Newtons and t in seconds. If the pulley was initially at rest, find its angular speed after 4.0 s.

Homework Equations


(I'm having trouble with Latex so excuse my non-greek)
T = AI
(net torque= angular acceleration*rotational inertia)
w = at  dw = a·dt You will need to integrate this.
(angular velocity = angular acceleration*time)
T = rF
(torque = length*force)


The Attempt at a Solution


w = (T)(t)/I  dw = ((T)/I)·(dt)  
rFt/I = w  (rF/I)(dt) = dw

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s

But this is incorrect. I am not sure how to handle this with the variable force being applied.

Some corrections in red above.

\omega-\omega_0=\frac{r}{I}\ \int_0^{\,4} F(t) dt

I don't think this is the integral you did.
 
No idea why I multiplied by time, thanks guys. :D
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top