Angular Velocity On Pulley After Variable Force

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Homework Help Overview

The discussion revolves around a problem involving a pulley with a specified rotational inertia and radius, subjected to a time-varying tangential force. The original poster seeks to determine the angular speed of the pulley after a given time period, while grappling with the complexities introduced by the variable force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the need to integrate the force function over time to find the total effect on angular velocity. There are questions regarding the multiplication by time in the original poster's calculations, and some participants suggest reconsidering the integration approach.

Discussion Status

The discussion is ongoing, with participants providing insights into the integration of the force function and questioning the original poster's reasoning. Some corrections have been noted, but no consensus has been reached regarding the correct approach to the problem.

Contextual Notes

There is mention of difficulties with LaTeX formatting and the original poster's uncertainty about handling the variable force. The problem setup includes specific values for rotational inertia and radius, as well as the functional form of the applied force.

Jshumate
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Homework Statement


A pulley having a rotational inertia of 1.1 10-3 kg·m2 about its axle and a radius of 23 cm is acted on by a force, applied tangentially at its rim, that varies in time as F = 0.50t + 0.30t2, where F is in Newtons and t in seconds. If the pulley was initially at rest, find its angular speed after 4.0 s.

Homework Equations


(I'm having trouble with Latex so excuse my non-greek)
T = AI
(net torque= angular acceleration*rotational inertia)
w = at
(angular velocity = angular acceleration*time)
T = rF
(torque = length*force)


The Attempt at a Solution


w = (T)(t)/I
rFt/I = w

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s

But this is incorrect. I am not sure how to handle this with the variable force being applied.
 
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Jshumate said:

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s


why did you multiplied by the time?

ehild
 
Jshumate said:

Homework Statement


A pulley having a rotational inertia of 1.1 10-3 kg·m2 about its axle and a radius of 23 cm is acted on by a force, applied tangentially at its rim, that varies in time as F = 0.50t + 0.30t2, where F is in Newtons and t in seconds. If the pulley was initially at rest, find its angular speed after 4.0 s.

Homework Equations


(I'm having trouble with Latex so excuse my non-greek)
T = AI
(net torque= angular acceleration*rotational inertia)
w = at  dw = a·dt You will need to integrate this.
(angular velocity = angular acceleration*time)
T = rF
(torque = length*force)


The Attempt at a Solution


w = (T)(t)/I  dw = ((T)/I)·(dt)  
rFt/I = w  (rF/I)(dt) = dw

I assume I have to integrate the force function over the period of time. The integral of F(t) from 0 to 4 = 10.4.
(10.4 N)(0.23 m)(4 s)/(1.1 10-3kg·m2) = w
w = 8698 rad/s

But this is incorrect. I am not sure how to handle this with the variable force being applied.

Some corrections in red above.

[tex]\omega-\omega_0=\frac{r}{I}\ \int_0^{\,4} F(t) dt[/tex]

I don't think this is the integral you did.
 
No idea why I multiplied by time, thanks guys. :D
 

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