Another differentiation problem

  • Thread starter Thread starter b521
  • Start date Start date
  • Tags Tags
    Differentiation
b521
Messages
10
Reaction score
0

Homework Statement



If z² = x² + y²
and
dx/dt = 2
and
dy/dt = 3

Find dz/dt when x=5 and y=12

Homework Equations



I used
mathtex.cgi?\frac{dy}{dt}%20\%20\%20=%20\%20\%20\frac{dy}{dx}\cdot%20\frac{dx}{dt}.gif


The Attempt at a Solution



But I resulted in:

2z dz/dt = 2x(dx/dt) + 2y(dy/dt)

Plugged in x,y,dx/dt, and dy/dt to get:

2z (dz/dt) = 2(5)(2) + 2(12)(3)

dz/dt = 80/2z
= 40/z
But the answer is +/- 46/13

Anyone know where I went wrong?
 

Attachments

  • mathtex.cgi?\frac{dy}{dt}%20\%20\%20=%20\%20\%20\frac{dy}{dx}\cdot%20\frac{dx}{dt}.gif
    mathtex.cgi?\frac{dy}{dt}%20\%20\%20=%20\%20\%20\frac{dy}{dx}\cdot%20\frac{dx}{dt}.gif
    611 bytes · Views: 443
Last edited:
Physics news on Phys.org
b521 said:

Homework Statement



If z² = x² + y²
and
dx/dt = 2
and
dy/dt = 3

Find dz/dt when x=5 and y=12

Homework Equations



I used
mathtex.cgi?\frac{dy}{dt}%20\%20\%20=%20\%20\%20\frac{dy}{dx}\cdot%20\frac{dx}{dt}.gif


The Attempt at a Solution



But I resulted in:

2z dz/dt = 2x(dx/dt) + 2y(dy/dt)

Plugged in x,y,dx/dt, and dy/dt to get:

2z (dz/dt) = 2(5)(2) + 2(12)(3)

dz/dt = 80/2z
= 40/z



But the answer is +/- 46/13
5*2 + 12*3 = 46, not 40. Also, when x = 5 and y = 12, z = +/- 13.
b521 said:
Anyone know where I went wrong?
 
Ahhh thank you very much!
 
Thread 'Use greedy vertex coloring algorithm to prove the upper bound of χ'
Hi! I am struggling with the exercise I mentioned under "Homework statement". The exercise is about a specific "greedy vertex coloring algorithm". One definition (which matches what my book uses) can be found here: https://people.cs.uchicago.edu/~laci/HANDOUTS/greedycoloring.pdf Here is also a screenshot of the relevant parts of the linked PDF, i.e. the def. of the algorithm: Sadly I don't have much to show as far as a solution attempt goes, as I am stuck on how to proceed. I thought...
Back
Top