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Another probablility question

  1. Sep 29, 2013 #1
    1. The problem statement, all variables and given/known data

    Three friends (A, B, and C) will participate in a round-robin tournament in which each one plays both of the others. Suppose that P(A beats B) = 0.7, P(A beats C) = 0.3, P(B beats C) = 0.6, and that the outcomes of the three matches are independent of one another.

    (d) What is the probability that each person wins one match? (Hint: There are two different ways for this to happen.)


    2. Relevant equations

    not sure if there is a relevant equation to this


    3. The attempt at a solution

    (d) What is the probability that each person wins one match? (Hint: There are two different ways for this to happen.)

    so A, B and C would need to win a match

    P(A beats B) = 0.7 (A wins)
    P(A beats C) = 0.3, so we would take 1-.3=0.7 to figure out probability of C winning
    P(B beats C) = 0.6 (B wins)

    P=(0.7)(0.7)(0.6)=0.294 THIS IS INCORRECT
     
  2. jcsd
  3. Sep 29, 2013 #2

    tiny-tim

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    hi needstatshelp! welcome to pf! :smile:
    you've only done the probability for one of the two different ways :wink:
     
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