Answer: The mass of the piston is 16.2 kg.Weight of a Piston: 16.2 kg

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The discussion centers on calculating the mass of a piston in a vertical cylindrical tank containing an ideal gas. Given the conditions of 1.80 mol of gas at 1.05 atm and 22.0°C, the mass of the piston is determined to be approximately 16.2 kg using the equation pV=nRT. The pressure of the gas is influenced by its volume and temperature, while the weight of the piston contributes to the force exerted on the gas. This relationship highlights the balance between gas pressure and the weight of the piston in the system. Understanding these dynamics is crucial for solving related physics problems.
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Homework Statement



A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 1.05 atm at 22.0^\circ C. The round part of the tank has a radius of 10.0 cm , and the gas is supporting a piston that can move up and down in the cylinder without friction.

What is the mass of this piston?

Homework Equations



pV=nRT

The Attempt at a Solution



.05*1 \; atm*.01\pi \: m^2/9.8 \approx 16.2 kg
 
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james brug said:

Homework Statement



A vertical cylindrical tank contains 1.80 mol of an ideal gas under a pressure of 1.05 atm at 22.0^\circ C. The round part of the tank has a radius of 10.0 cm , and the gas is supporting a piston that can move up and down in the cylinder without friction.

What is the mass of this piston?

Homework Equations



pV=nRT

The Attempt at a Solution



.05*1 \; atm*.01\pi \: m^2/9.8 \approx 16.2 kg
What determines the pressure of the gas in the cylinder? How much of that force (per unit area) is due to the weight of the pistion?

AM
 

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