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Hi Everybody,

I am having a problem with a homework question and think that I have finally got it right this time! Can somebody verify my work on this problem and let me know if I did indeed do this problem correctly? If not then can anybody help point me in the right direction and get me back on track?

The HW deals with Kinematics in 2-Dimensions

THANK YOU!!!

- Doug

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The Question

A rock climber throws a small first aid kit to another climber who is higher up the mountain. The initial velocity of the kit is 6.93 m/s at an angle of 66.5 degrees above the horizontal. At the instant when the kit is caught, it is traveling horizontally, so its vertical speed is zero. What is the vertical height between the two climbers?

My Set-Up of Variables

V_initial = 6.93 m/s

V_final - 0 m/s

A = 9.80 m/s^2

Y = ? (SOLVE FOR)

T = ?

My Equation & Work

V^2=V_initial^2+2AY --> Y = (V_final^2 - V_initial^2)/2A --> (0^2 - 6.93^2)/2(9.80) --> 48.02/19.6 --> 2.45m

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# Homework Help: Answer Verification *Please*

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