Slimsta
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Homework Statement
$g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt$
whats g'(x)...
Homework Equations
The Attempt at a Solution
how to find the antiderivative of sqrt(1-t^2)?
Use the Fundamental Theorem of Calculus to find g'(x). You will also need the chain rule since your integral isn't strictly a function of just x, but is a function of sin(x).Slimsta said:Homework Statement
g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt
whats g'(x)...
Homework Equations
The Attempt at a Solution
how to find the antiderivative of sqrt(1-t^2)?
Slimsta said:how to find the antiderivative of sqrt(1-t^2)?
Mark44 said:Use the Fundamental Theorem of Calculus to find g'(x) …
Slimsta said:Homework Statement
g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt
whats g'(x)...
Homework Equations
The Attempt at a Solution
how to find the antiderivative of sqrt(1-t^2)?
The problem does not ask you to find the anti-derivative nor is it necessary.rock.freak667 said:Try t=sin(u) or t=cos(u)
<br /> <br /> okay, that make sense but what if i have a function like this:<br /> $\int _{3\pi /4}^{\pi }(3 \sec ^2x -\frac{6 }{\pi })dx$<br /> <br /> this is confusing me :SHallsofIvy said:The problem does not ask you to find the anti-derivative nor is it necessary.
Letting y= sin(x), this is
g(y)=\int_2^y \sqrt{1- t^2} dt[/itex]<br /> You can find dg/dy directly from the "Fundamental Theorem of Calculus" and then use the chain rule to find dg/dx.