Antiderivative of a function problem

Slimsta
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Homework Statement


$g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt$
whats g'(x)...

Homework Equations


The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?
 
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Try t=sin(u) or t=cos(u)
 
I have edited your formula slightly so that it now shows g(x), not just (x). You had extra $ characters that shouldn't have been there.
Slimsta said:

Homework Statement


g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt
whats g'(x)...


Homework Equations





The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?
Use the Fundamental Theorem of Calculus to find g'(x). You will also need the chain rule since your integral isn't strictly a function of just x, but is a function of sin(x).
 
Hi Slimsta! :smile:
Slimsta said:
how to find the antiderivative of sqrt(1-t^2)?
Mark44 said:
Use the Fundamental Theorem of Calculus to find g'(x) …

Just to add to what Mark44 :smile: says …

the beauty of using the Fundamental Theorem of Calculus is that you don't need to know the antiderivative. :wink:
 
Slimsta said:

Homework Statement


g(x)=\int _{2 }^{\sin x}\sqrt{1- t^2}dt
whats g'(x)...


Homework Equations





The Attempt at a Solution


how to find the antiderivative of sqrt(1-t^2)?

rock.freak667 said:
Try t=sin(u) or t=cos(u)
The problem does not ask you to find the anti-derivative nor is it necessary.
Letting y= sin(x), this is
g(y)=\int_2^y \sqrt{1- t^2} dt[/itex]<br /> You can find dg/dy directly from the &quot;Fundamental Theorem of Calculus&quot; and then use the chain rule to find dg/dx.
 
HallsofIvy said:
The problem does not ask you to find the anti-derivative nor is it necessary.
Letting y= sin(x), this is
g(y)=\int_2^y \sqrt{1- t^2} dt[/itex]<br /> You can find dg/dy directly from the &quot;Fundamental Theorem of Calculus&quot; and then use the chain rule to find dg/dx.
<br /> <br /> okay, that make sense but what if i have a function like this:<br /> $\int _{3\pi /4}^{\pi }(3 \sec ^2x -\frac{6 }{\pi })dx$<br /> <br /> this is confusing me :S
 
That's a definite integral, so that gives you the signed area between the limits of integration, or just a number. What's the derivative of a constant?

A variable (other than x since x would be the dummy variable) in either of the limits of integration would make it a function.
 
hh i already figured that out.. i just took out the 3 and then it becomes tanx - 2/pi x and then its easy..
 
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