Antisymmetry of final State Requiring L = 1

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SUMMARY

The discussion centers on the requirement of orbital angular momentum L = 1 in the reaction d + pion- → n + n, where d represents a deuteron. The conclusion is drawn from the combination of the deuteron's spin (1) and the pion's spin (0), along with the antisymmetry of the final state. The antisymmetry necessitates that the two neutrons possess an odd total angular momentum, which can only be satisfied by L = 1 due to angular momentum conservation laws.

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Mr. Lapage
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I'm currently trying to solidify the notion of parity conservation in my head and saw this example on wikepdia, and am just wondering why in the reaction d + pion- ---> n + n (where d is a deuteron)

"Using the fact that the deuteron has spin one and the pion spin zero together with the antisymmetry of the final state they concluded that the two neutrons must have orbital angular momentum L=1"

Why does the antisymmetry of the final state require that the angular momentum = 1?

See the example on wikipedia here, http://en.wikipedia.org/wiki/Parity_(physics)#Parity_of_the_pion
 
Physics news on Phys.org
parity = (-1)^L

we must have L = 1,3,5...

but only L = 1 is compatible with angular momentum conservation
 

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